Respuesta :
Answer:
(a) The shear plane angle is: ∅=26. 86°
(b) the shear strain for the operation is: γ = 2.155234
Explanation:
In orthogonal cutting, the wedge-shaped tool used in the cutting edge is perpendicular to the direction of motion.
(a) The shear plane angle is:
shear plane angle is the angle between shear plane and the cutting velocity in orthogonal cutting.
r= t[tex]1[/tex] ÷ t[tex]2[/tex]
Where, t[tex]1[/tex]= Initial thickness before the cut
t[tex]2[/tex]= deformed thickness
r = cutting ratio, which signifies the ratio of chip thickness of metal before cutting to the thickness after cutting.
r = 0.30 mm ÷ 0.65 mm
= 0.461538
∅ = tan∧[tex]^{-1}[/tex] ( 0.461538 cos 15 ÷ ( 1 - 0.461538 sin 15) )
= tan∧[tex]^{-1}[/tex] (0.506289)
∅=26. 86°
(b) the shear strain for the operation is:
Shear strain is the stress tangent of an angle, that acts parallel to a material cross section.
γ = cot 26.86 + tan (26.86 - 15)
=1.974523 + 0.210004
γ = 2.155234
