Answer: The [tex][H_3O^+][/tex] is [tex]1.55\times 10^{-10}M[/tex]
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pOH is calculated by taking negative logarithm of hydroxide ion concentration.
[tex]pOH=-\log [OH^-][/tex]
Putting in the values:
[tex]pOH=-\log[6.4\times 10^{-5}][/tex]
[tex]pOH=4.19[/tex]
[tex]pH+pOH=14[/tex]
[tex]pH=9.81[/tex]
[tex]9.81=-\log [H_3O^+][/tex]
[tex][H_3O^+]=1.55\times 10^{-10}[/tex]
Thus the [tex][H_3O^+][/tex] is [tex]1.55\times 10^{-10}M[/tex]
The value of [H₃O⁺] will be "1.55 × 10⁻¹⁰ M". To understand the calculation, check below.
According to the question,
The value of [OH⁻] = 6.4 × 10⁻⁵
By taking hydroxide ion concentration log,
→ pOH = log[OH⁻]
By putting the value of [OH⁻],
pOH = log[6.4 × 10⁻⁵]
= 4.19
hence,
→ pH + pOH = 14
9.81 = log [H₃O⁺]
[H₃O⁺] = 1.55 × 10⁻¹⁰ M
Thus the above answer is correct.
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