Answer: 24 moles of [tex]SnF_2[/tex] are produced.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]{\text{Moles of} H_2}=\frac{48g}{2g/mol}=24moles[/tex]
[tex]Sn+2HF\rightarrow SnF_2+H_2[/tex]
According to stoichiometry :
1 mole of [tex]H_2[/tex] is accompanied with = 1 mole of [tex]SnF_2[/tex]
Thus 24 moles of [tex]H_2[/tex] is accompanied with =[tex]\frac{1}{1}\times 24=24moles[/tex] of [tex]SnF_2[/tex]
Thus 24 moles of [tex]SnF_2[/tex] are produced.
