Answer:
200 grams of NaOH are produced with the reaction of 5.00 moles of water
Explanation:
First of all you apply a rule of three to know the amount of moles of NaOH as follows: if 2 moles of water produce 2 moles of NaOH, 5 moles of water how many moles would they produce?
[tex]moles of NaOH=\frac{5 moles of water*2 moles of NaOH}{2 moles of water}[/tex]
moles of NaOH= 5
Being:
the molar mass of NaOH is: 23 g/mole + 16 g/mole + 1 g/mole= 40 g/mole
Then a rule of three applies as follows: if in 1 mole there are 40 g of NaOH, in 5 moles how much mass is there?
[tex]mass=\frac{5 moles*40g}{1 mole}[/tex]
mass= 200 g
200 grams of NaOH are produced with the reaction of 5.00 moles of water
