Answer:
The probability that a randomly selected monthly cell phone bill is less than $95 is 0.9772
Step-by-step explanation:
The average monthly household cellular phone bill is $73.
[tex]\mu = 73[/tex]
Local monthly household cell phone bills are normally distributed with a standard deviation of $11.
[tex]\sigma = 11[/tex]
We are supposed to find the probability that a randomly selected monthly cell phone bill is less than $95 i.e.P(x<95)
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{95-73}{11}[/tex]
Z=2
Refer the z table for p value
So,p value = 0.9772
Hence the probability that a randomly selected monthly cell phone bill is less than $95 is 0.9772
