Respuesta :
Answer: 15.62 moles of [tex]HgO[/tex] are needed to produce 250.0 g of [tex]O_2[/tex]
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} O_2=\frac{250.0g}{32g/mol}=7.812moles[/tex]
[tex]2HgO\rightarrow 2Hg+O_2[/tex]
According to stoichiometry :
1 mole of [tex]O_2[/tex] is produced from decomposition of = 2 moles of [tex]HgO[/tex]
Thus 7.812 moles of [tex]O_2[/tex] will be produced from decomposition of =[tex]\frac{2}{1}\times 7.812=15.62moles[/tex] of [tex]HgO[/tex]
Thus 15.62 moles of [tex]HgO[/tex] are needed to produce 250.0 g of [tex]O_2[/tex]
