Identify the equation in slope-intercept form for the line containing the point (−3,5) and parallel to y=−2/3x+53.

y=−3/2x+5/3

y=−2/3x+5

y=−2/3x+3

y=2/3x+5

Respuesta :

Answer:

y=−2/3x+3

Step-by-step explanation:

I graphed the point and the equation given below. I used the same slope in the new equation as the original equation. The y-intercept is 3 because the line goes through (0,3).

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Thus option C :  [tex]y = -\dfrac{2}{3}x + 3[/tex]  is correct.

Given that:

Equation of considered straight line:

[tex]y = -\dfrac{2}{3}x + 53[/tex]

Let the equation of the straight line that has to be found is given by:

[tex]y = mx + c[/tex]

It is given that the line is parallel to previous straight lines.

Which means  that slope of both the lines are same

or

[tex]m = -\dfrac{2}{3}[/tex]

Now since the second line passes through (-3,5), thus we have:

[tex]5 = -\dfrac{2}{3}\times -3 + c\\or\\c = 3[/tex]

Thus the needed equation of straight line is given by:

[tex]y = -\dfrac{2}{3}x + 3[/tex]

Thus option C :  [tex]y = -\dfrac{2}{3}x + 3[/tex]  is correct.

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