Answer: 8.57 ml of KOH is required to reach the equivalence point.
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]HNO_3[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is KOH.
We are given:
[tex]n_1=1\\M_1=0.120M\\V_1=60.0mL\\n_2=1\\M_2=0.840M\\V_2=?[/tex]
Putting values in above equation, we get:
[tex]1\times 0.120\times 60.0=1\times 0.840\times V_2\\\\V_2=8.57mL[/tex]
Thus 8.57 ml of KOH is required to reach the equivalence point.
