Respuesta :
Answer: The amount of carbon-14 left after 10 years is 25 g
Explanation:
Formula used :
[tex]a=\frac{a_o}{2^n}[/tex]
where,
a = amount of reactant left after n-half lives = ?
[tex]a_o[/tex] = Initial amount of the reactant = 100 g
n = number of half lives =[tex]\frac{\text {given time}}{\text {half life}}=\frac{10}{5}=2[/tex]
Putting values in above equation, we get:
[tex]a=\frac{100g}{2^2}[/tex]
[tex]a=\frac{100g}{4}=25g[/tex]
Therefore, the amount of carbon-14 left after 10 years is 25 g
