Answer:
16.48mL
Explanation:
The following data were obtained from the question:
Initial pressure (P1) = 1 atm
Initial temperature (T1) = 0°C = 0°C + 273 = 273K
Initial volume (V1) = 30mL
Final temperature (T2) = 27°C = 27°C + 273 = 300K
Final pressure (P2) = 2atm
Final volume (V2) =..?
Applying the general gas equation, the final volume of the gas can be obtained as follow:
P1V1/T1 = P2V2/T2
1 x 30/273 = 2 x V2/300
Cross multiply to express in linear form
273 x 2 x V2 = 30 x 300
Divide both side by 273 x 2
V2 = (30 x 300)/(273 x 2)
V2 = 16.48mL
Therefore, the new volume of the gas is 16.48mL
The volume of a sample of gas that starts at 1.00 atm, 0.00 degrees celsius, and 30.0 mL is 16.48mL. Details about volume can be found below..
The volume of an ideal gas can be calculated by using the following formula:
P1V1/T1 = P2V2/T2
Where;
1 × 30/273 = 2 × V2/300
0.109 = 2V2/300
32.97 = 2V2
V2 = 16.48mL
Therefore, the volume of a sample of gas that starts at 1.00 atm, 0.00 degrees celsius, and 30.0 mL is 16.48mL.
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