We have been given an equation [tex]\frac{3}{5}(30x-15)=72[/tex]. We are asked to choose the equations that have same value of x.
Let us solve our given problem.
[tex]\frac{3}{5}\cdot 30x-\frac{3}{5}\cdot 15=72[/tex]
[tex]3\cdot 6x-3\cdot 3=72[/tex]
[tex]18x-9=72[/tex]
Therefore, option C is the correct choice.
Now we will factor out 3 from above equation as:
[tex]3\cdot 6x-3\cdot 3=72[/tex]
[tex]3(6x-3)=72[/tex]
Therefore, option D is correct choice as well.
Let us solve for x.
[tex]\frac{3(6x-3)}{3}=\frac{72}{3}[/tex]
[tex]6x-3=24[/tex]
[tex]6x-3+3=24+3[/tex]
[tex]6x=27[/tex]
[tex]\frac{6x}{6}=\frac{27}{6}[/tex]
[tex]x=4.5[/tex]
Therefore, last option is correct as well.
