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A magnetic field between the poles of the electromagnet is uniform at any time, but its magnitude is increasing at the rate of 0.020T/s. The area of the conducting loop in the field is 120 cm2 , and the total circuit resistance, including the meter is 5.0 ohms. (a)Find the induced emf and the induced current in the circuit.(b) If the loop is replaced by one made of an insulator, what effect does this have on the induced emf and induced current?

Respuesta :

mavila18

Answer:

a) -2.4*10^-4 V

   4.8*10^-5 A

b)  emf = 0

   induced current = 0

Explanation:

a) The induced emf is given by the following formula:

[tex]emf=-\frac{d\Phi_B}{dt}=-\frac{d(AB)}{dt}[/tex]    ( 1 )

A: area of the loop = 120 cm^2 = 120 (10^-2)^2 = 0.012m^2

The area is constant and dB/dt = 0.020T/s

By replacing in  the values of the parameters in the equation (1) you obtain:

[tex]emf=-A\frac{dB}{dt}=-(0.012m^2)(0.020T/s)=-2.4*10^{-4}V[/tex]

The induced current is:

[tex]I=\frac{emf}{R}=\frac{2.4*10^{-4}V}{5.0\Omega}=4.8*10^{-5}A[/tex]

b) If the loop is made of an insulator, electrons in the wire does not feel the change in the magnetic flux. Due to that, there is no a work over the electrons, and consequantly, there is neither emf nor induced current.

onyebuchinnaji

(a) The magnitude of the induced emf is 2.4 x 10⁻⁴ V.

(b) The induced current is 4.8 x 10⁻⁵ A.

Induced emf

The magnitude of the induced emf is determined by applying Faraday's law of electromagnetic induction.

emf = dΦ/dt

emf = BA/t

where;

  • A is the area = 120 cm² = 0.012 m²

emf = (0.02 x 0.012)

emf = 2.4 x 10⁻⁴ V

Induced current

The induced current is calculated as follows;

emf = IR

I = emf/R

I = (2.4 x 10⁻⁴) / (5)

I = 4.8 x 10⁻⁵ A

Learn more about electromagnetic induction here: https://brainly.com/question/26334813