The engine whose temperature increased more for each increase of 1 cycles per second is; The second Engine
What is the Increase in Temperature?
1) We want to find the engine whose temperature increased more for each increase of 1 cycles per second.
Now, for the first engine, the increase in temperature is required when there is an increase of 1 cycle of rotation per second we need to find the slope. Thus,
Slope = Δy/Δx = (28.8 - 26.4)/(11 - 8)
Increase in temperature per 1 cycle of rotation increase = 0.8
For the second engine, the slope is;
Slope = (28 - 22)/(5 - 0)
Slope = 1.2
Thus, the second engine has temperature that increased more for each increase of 1 cycles per second.
2) Since the rate of increase in Engine 2 is higher, it menas it will be hotter at 20 cycles rotation per second
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