Answer:
b. 2 and 3
Step-by-step explanation:
Solve for x
[tex]x^{2} - 5x + 6 = 0[/tex]
Now factor
[tex](x - 2)(x - 3) <---[/tex] It would be -2 and -3 because they add up to -5 and multiply to be 6 (a negative times a negative always equal a positive)
Don't forget that it's still equal to 0
[tex](x-2)=0[/tex] [tex](x-3)=0[/tex]
Now solve for x in both equations
[tex]x-2=0[/tex] [tex]x-3=0[/tex]
[tex]+2[/tex] [tex]+2[/tex] add 2 to both sides [tex]+3[/tex] [tex]+3[/tex] add 3 to both sides
[tex]x=2[/tex] [tex]x = 3[/tex]
