contestada

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . NaOH(aq). Calculate the amount of Ga ( s ) Ga(s) that can be deposited from a Ga ( III ) Ga(III) solution using a current of 0.880 A 0.880 A that flows for 30.0 min .

Respuesta :

dsdrajlin

Answer:

0.382 g

Explanation:

Let's consider the reduction of gallium (III) to gallium that occurs in the electrolysis.

Ga³⁺ + 3 e⁻ → Ga

We can establish the following relations:

  • 1 minute = 60 second
  • 1 Ampere = 1 Coulomb / second
  • The charge of 1 mole of electrons is 96,468 Coulomb (Faraday's constant)
  • 1 mole of gallium is deposited when 3 moles of electrons circulate.
  • The molar mass of gallium is 69.72 g/mol

We will use this that to determine the mass of gallium deposited from a Ga(III) solution using a current of 0.880 A that flows for 30.0 min

[tex]30.0min \times \frac{60s}{1min} \times \frac{0.880c}{s} \times \frac{1mole^{-} }{96,468c} \times \frac{1molGa}{3 mole^{-}} \times \frac{69.72g}{1molGa} = 0.382 g[/tex]

Otras preguntas