A clown is shot out of cannon with a velocity of 200 feet per second at an angle of 24°
with the horizontal. Find the vertical and horizontal components of the velocity of this clown.

Respuesta :

Answer:

Vertical component of velocity is [tex]81.35 ft/sec.[/tex]

Horizontal component of velocity is  [tex]182.6 ft/sec[/tex].

Step-by-step explanation:

Horizontal component of velocity is defined as:

[tex]v_{x} = v\times cos\theta[/tex]

Vertical component of velocity is defined as:

[tex]v_{y} = v\times sin\theta[/tex]

Where [tex]v_{x} , v_{y}[/tex] are the horizontal and vertical components of velocity.

[tex]v[/tex] is the actual velocity and

[tex]\theta[/tex] is the angle with horizontal axis at which the object was thrown.

Here, we are provided with the following:

[tex]v = 200 ft/sec[/tex]

[tex]\theta = 24^\circ[/tex]

[tex]v_{x} = 200 \times cos24^\circ\\\Rightarrow 200 \times 0.913\\\Rightarrow v_{x} = 182.6 ft/sec[/tex]

[tex]v_{y} = 200 \times sin24^\circ\\\Rightarrow 200 \times 0.407\\\Rightarrow v_{y} = 81.35 ft/sec[/tex]

So, Vertical component of velocity is [tex]81.35 ft/sec.[/tex]

Horizontal component of velocity is  [tex]182.6 ft/sec[/tex].

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