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A closed loop conductor with radius 1.5 m is located in a changing magnetic field. If the max emf induced in the loop is 7.0 V, what is the max rate which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies

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ogbe2k3

Answer:

0.99 T/s

Explanation:

Solution

From the example given, we recall that,

The emf induced in the loop is V = 7.0

Closed loop conductor with r = 1.5 m

∅B = BA

The emf =  d∅B/ dt

which is

d/dt  (BA)

so,

emf = A dB/ dt

emf =πr² dB/ dt

Now,

dB/dt = emf /πr²

=  7/π * (1.5)²

Therefore dB/dt = 0.99 T/s

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