Answer:
[tex]-64=64cos(\pi )+64i/ sin(\pi )[/tex]
Step-by-step explanation:
For a complex number a + bi, polar form is given by [tex]r(cos(0)+ i sin(0))[/tex], where [tex]r = \sqrt{a^2+b^2}[/tex] and [tex]a = atan(\frac{b}{a} )[/tex]
In this case, we have [tex]a = -64[/tex] and [tex]b=0[/tex]
Therefore, [tex]r = \sqrt{(-64)^2+(0)^2} =64[/tex]
Also, [tex]0 = atan(\frac{0}{-64} )+\pi =\pi[/tex]
Which means that, [tex]-64=64cos(\pi )+64i/ sin(\pi )[/tex]!!!
I'm happy i finally got it!
