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A GAS SAMPLE HAS A TEMPERATURE OF 18 CELSIUS WITH AN UNKNOWN VOLUME. THE SAME GAS HAS A VOLUME OF 436 ML WHEN THE TEMPERATURE IS 91 CELSIUS WITH NO CHANGE IN THE PRESSURE AND AMOUNT OF GAS
WHAT WAS THE INITIAL VOLUME IN MILLILITERS OF THE GAS

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dsdrajlin

Answer:

349 mL

Explanation:

Given data

  • Initial volume (V₁): unknown
  • Initial temperature (T₁): 18 °C + 273.15 = 291 K
  • Final volume (V₂): 436 mL
  • Final temperature (T₂): 91°C + 273.15 = 364 K

If we consider the has as an ideal gas, we can calculate the initial volume of the gas sample using the Charles' law.

V₁ / T₁ = V₂ / T₂

V₁ = V₂ × T₁ / T₂

V₁ = 436 mL × 291 K / 364 K = 349 mL

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