Answer:
2.63 atm.
Explanation:
Given,
Volume,V = 4.44 L
n = 0.481 mol of O₂
Temperature, T = 22.6°C = 22.6 + 273 = 295.6 K
Using ideal gas law
[tex]P = \dfrac{nRT}{V}[/tex]
[tex]P = \dfrac{0.481\times 0.0821 \times 295.6}{4.44}[/tex]
P = 2.63 atm.
Pressure of the tank is equal to 2.63 atm.
