Answer:
The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"
Step-by-step explanation:
Given values:
[tex]2xy =6.....(a)\\\\x-y= 3.....(b)\\\\[/tex]
After solve equation (a) we get
[tex]\ equation: \\\\2xy= 6\\\\xy =\frac{6}{2} \\\\xy = 3.....(x)\\\\[/tex]
After solve equation (b) we get
[tex]\ equation: \\\\x-y =3\\\\x= 3+y....(x1)\\[/tex]
put the value of x in to equation (x)
[tex](3+y)y = 3\\[/tex]
[tex]y^2+3y-3=0\\\\\ compare \ the \ value \ with \ ay^2+by+c=0\\a= 1\\b=3\\c=-3\\\ Formula: \\y= \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\y= \frac{-3\pm \sqrt{9+12}}{2}\\y= \frac{-3\pm \sqrt{21}}{2}\\[/tex]
The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29
