What are the intercepts of the line

Answer:
y intercept (0,-32)
x intercept (3.2,0)
Step-by-step explanation:
To find the y intercept set x = 0 and solve for y
y = 10x -32
y = 0-32
y = -32
(0,-32)
To find the x intercept set y = 0 and solve for x
y = 10x -32
0 = 10x -32
Add 32 to each side
32 = 10x
Divide by 10
32/10 = x
(3.2,0)
Answer:
[tex]y-intercept(0,-32)\\\\x-intercept(\frac{16}{5},0)[/tex]
Step-by-step explanation:
The y-intercept happens where x is 0, and the x-intercept if where y is 0. You can use this knowledge to find the intercepts.
This equation is written in slope-intercept form:
[tex]y=mx+b[/tex]
where b is the y-intercept, so the y-intercept is -32.
To find the x intercept, insert 0 as the value of y:
[tex]0=10x-32[/tex]
Solve for x. Add 32 to both sides:
[tex]0+32=10x-32+32\\\\32=10x[/tex]
Divide both sides by 10:
[tex]\frac{32}{10}=\frac{10x}{10} \\\\x=\frac{32}{10} =\frac{16}{5}[/tex]
The x-intercept is at [tex]\frac{16}{5}[/tex] or [tex]3.2[/tex] .
Find the points:
[tex]y-intercept(0,-32)\\x-intercept(\frac{16}{5},0)[/tex]
Finito.