Explanation:
Th electric force between charges is inversely proportional to the square of distance between them. It means,
[tex]F\propto \dfrac{1}{r^2}[/tex]
Initial distance, r₁ = 2 cm
Final distance, r₂ = 0.25 cm
Initial force, F₁ = 1 N
We need to find the electric force between charges if the new separation of 0.25 cm. So,
[tex]\dfrac{F_1}{F_2}=(\dfrac{r_2}{r_1})^2\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1\times 2^2}{(0.25)^2}\\\\F_2=64\ N[/tex]
So, the new force is 64 N if the separation between charges is 64 N.
