A bag contains 5 red marbles, 4 blue marbles and 7 green marbles. If three marbles
are drawn out of the bag, what is the exact probability that all three marbles drawn
will be red?

Respuesta :

Answer:

The exact probability that all three marbles drawn  will be red is [tex]\frac{1}{56}[/tex]

Step-by-step explanation:

Number of red marbles = 5

Number of blue marbles = 4

Number of Green marbles = 7

Total Number of marbles = 5+4+7=16

We are given that three marbles  are drawn out of the bag

Probability of getting 1 red marble on first draw=[tex]\frac{5}{16}[/tex]

Probability of getting 1 red marble on second draw= [tex]\frac{4}{15}[/tex]

Probability of getting 1 red marble on third draw=[tex]\frac{3}{14}[/tex]

So,the exact probability that all three marbles drawn  will be red=[tex]\frac{5}{16} \times \frac{4}{15} \times \frac{3}{14}=\frac{1}{56}[/tex]

Hence The exact probability that all three marbles drawn  will be red is [tex]\frac{1}{56}[/tex]