In a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly selects one card, one tile, and one disc.
Find the probability the player selects a card with S or E, a tile with 2, and a red disc.

This probability is defined by the sum of the probability of getting a card with S, and a probability of getting a card with E. Remeber, when the probability involves "or", that means sum.

[tex]P_{S \ or \ E} =\frac{1+1}{4}=\frac{2}{4} =\frac{1}{2}[/tex]

Probability of a tile with 2.

There are two tiles only, and one of them is numbered 2. So, its probability is

[tex]P_{2}=\frac{1}{2}[/tex]

Probability of a red disc.

There are two discs only. So, the probability of getting a red disc is

[tex]P_{red}=\frac{1}{2}[/tex]

Now, the combined probabilty of all these events can be found by multiplying, because we want to now the chances of getting all these results which are independent.

[tex]P_{total}=\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} =\frac{1}{8}[/tex]

Therefore, the probability is 1/8.

In a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly selects one card, one tile, and one disc. Find the probability the player selects a card with S or E, a tile with 2, and a red disc.

Respuesta :

The probability is 1/8.

Probability of a card with S or E.

Probability of a tile with 2.

Probability of a red disc.

Otras preguntas

In a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly selects one card, one tile, and one disc.
Find the probability the player selects a card with S or E, a tile with 2, and a red disc.