On a coordinate plane, a parabola opens up with solid circles along the parabola at (negative 6, 5), (negative 5, 0), (negative 4, negative 3), (negative 3, negative 4), (negative 2, negative 3), (negative 1, 0), (0, 5).
What is the vertex of the parabola in the graph?

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Respuesta :

jaycie5223 jaycie5223 · Answer 1 · 2020-05-09T04:17:46+02:00

Answer:

the answer is (-3,-4)

Step-by-step explanation: -3, -4

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sheenuvt12 sheenuvt12 · Answer 2 · 2022-07-28T03:58:58+02:00

The vertex of the parabola is (-3, -4)

A parabola is defined as a set of points in a plane which are equidistant from a straight line or directrix and focus.

Given:

The solid circles along the parabola are:

(-6, 5), (-5, 0), (-4, -3), (-3, -4), (-2, -3), (-1, 0), (0, 5).

As, the minimum point of y occurs at (-3, -4).

So, the x-intercept of the parabola is

x=-5 or x=-1

x+5=0 or x+1=0

(x+5)(x+1)=0

x² + 6x+ 5 =0

Now, vertex of equation at axis of symmetry x= -b/2a

x= -6/2 = -3

and, f(-3)= -3 * (-3) + 6(-3) + 5

f(-3)= -4

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