Complete Question
Despite the destruction from Hurricane Katrina in Sept 2005,the lowest pressure for a hurricane in the Atlantic Ocean was measured several weeks after Katrina. Hurricane Wilma registered at atmospheric pressure of 88.2 kPa on Oct 19, 2005,about 2 kPa lower than Hurricane Katrinia. What was the difference between the two hurricanes in:
millimeters of Hg? ___ mm Hg
atmospheres? ___ atm
millibars? ___ mb
Answer:
The difference in pressure in mm of Hg is [tex]Pg = 15.05 \ mm\ Hg[/tex]
The difference in pressure in atm is [tex]P_{atm} = 0.0198 \ atm[/tex]
The difference in pressure in millibar is [tex]P_{bar} = 20 \ mbar[/tex]
Explanation:
From the question we are told that
The pressure of Hurricane Wilma is [tex]P = 88 kPa[/tex]
The difference is pressure is [tex]\Delta P =2\ k Pa[/tex]
Generally
[tex]1\ atm = 1.01 *10^5 \ Pa[/tex]
[tex]1 \ atm = 760\ mmHg[/tex]
The pressure difference in mm Hg is mathematically evaluated as
[tex]Pg = \Delta P * \frac{1000 Pa}{1kPa} * \frac{1\ atm}{1.01 *10^5} * \frac{760 mm Hg}{1 \ atm}[/tex]
Substituting the value
[tex]Pg = 2 kPa * \frac{1000 Pa}{1kPa} * \frac{1\ atm}{1.01 *10^5} * \frac{760 mm Hg}{1 \ atm}[/tex]
[tex]Pg = 15.05 \ mm\ Hg[/tex]
The pressure difference in atm is
[tex]P_{atm } = 2kPa * \frac{1000}{1\ kPa} *\frac{1 \ atm}{1.01 *10^5 Pa}[/tex]
[tex]= 0.0198 \ atm[/tex]
The pressure in millibars is
[tex]= 2kPa * \frac{1000Pa}{1 kPa} * \frac{1\ bar }{1*10^5 Pa} * \frac{1000 \ milli bar}{1 bar}[/tex]
[tex]= 20 \ m bar[/tex]
