Answer:
x = -1, x = 1
Step-by-step explanation:
Factor the equation. (It's a difference of squares, so we know the form will be (a-b)(a+b).)
[tex]y = x^{2} - 1\\y = (x-1)(x+1)[/tex]
Test this by FOILing it out, if you're unsure. This is something it can be good to memorize!
Set it equal to 0.
[tex]0 = (x+1)(x-1)[/tex]
Separate the two parenthetical expressions by the Zero Product Property.
[tex]0 = x+1\\0 = x-1[/tex]
Solve for x!
[tex]x=-1, x=1[/tex]
