1. An object (m = 500 g) with an initial speed of 0.2 m/s collides with another object (m = 1.5 kg) which was at rest before the collision. Calculate the resulting speed for an inelastic collision (when they stick together). 2. A small object (m = 200 g) collides elastically with a larger object (m = 1000 g), which was at rest before the collision. The incoming speed of the smaller object was 1.0 m/s. The speed of the larger object after the collision is 0.33 m/s. Calculate the resulting speed and determine the direction for the smaller object after the collision when it rebounds. (Watch out for the directions of the motions and use respective signs for the velocities and momentums.)

mv = ( M +m) V , m and M are masses of small and large object , v is the velocity of small object before collision and V is the velocity of both the objects together after collision .

.5 x .2 = (1.5 + .5)V

V = .05 m /s

2 ) We shall use formula for velocity of object after elastic collision as follows

v₁ = [tex]\frac{(m_1-m_2)}{(m_1+m_2)} u_1+\frac{2m_2u_2}{(m_1+m_2)}[/tex]

m₁ and m₂ are masses of first and second object u₁ and u₂ are their initial velocity and v₁ and v₂ are their final velocity.

Putting the values

= [tex]\frac{(200-1000)}{(1000+200)} \times 1 +\frac{2 \times1000\times0}{(1000+200)}[/tex]

= - .66 m /s

Since the sign is negative so it will be in opposite direction .

tallinn tallinn · Answer 2 · 2022-04-07T15:47:09+02:00

1. The resultant speed for an inelastic collision is =.05 m /s

2. When The direction for the smaller object the collision when it rebounds is = -.66 m /s

What is Momentum of Law?

Conservation of momentum is refer to a major law of physics that states that the momentum of a system is constant if no external forces are acting on the system. when It is embodied in Newton’s First Law or The Law of Inertia.

1. We are involving the conservation of momentum law to solve the problem.

mv is = ( M +m) V, m, and M are masses of the small and large objects, v is the velocity of a small object before the collision and also V is the velocity of both the objects together after the collision.

Then .5 x .2 = (1.5 + .5)V

Therefore, V = .05 m /s

2. We shall use the formula for the velocity of the object behind the elastic collision as follows

After that, v₁ = (m₁-m₂)/(m₁+m₂)u1 + 2m₂u₂/(m₁+m₂)

m₁ and m₂ are masses of the first and second objects u₁ and u₂ are their initial velocity and v₁ and v₂ are their final velocity.

Putting the values

Now, = (200-1000)/(1000+200) × 1 + 2×1000×0/(1000+200)

Thus, = - .66 m /s

When the sign is negative so it will be in opposite direction.

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