Answer:
The resistance of wire #1 is twice as high as that of wire
Explanation:
For resistance of a wire the formula is as follows
R = ρ l / s where ρ is a constant called specific resistance , l is length and s is cross sectional area . If r be the radius of cross section
R = ρ l / π r²
For first wire , putting the given values in the equation
R₁ = ρ L/ π b²
For second wire,
R₂ = ρ 2L/ π 4b²
[tex]\frac{R_1}{R_2} =\frac{4}{2}[/tex]
= 2
The resistance of wire #1 is twice as high as that of wire
