Respuesta :
Explanation:
We have,
The most probable speed of an oxygen molecule in the gas phase at room temperature is 450 m/s.
The formula of the most probable speed of a gas molecule is given by :
[tex]v_p=\sqrt{\dfrac{2RT}{M}}[/tex]
So,
[tex]450=\sqrt{\dfrac{2RT}{M}}\\\\\dfrac{RT}{M}=\dfrac{450^2}{2}\\\\\dfrac{RT}{M}=101250\ .....(1)[/tex]
The RMS speed of the gas molecule is given by :
[tex]v_{rms}=\sqrt{\dfrac{3RT}{M}}\\\\v_{rms}=\sqrt{3\times \dfrac{RT}{M}}[/tex]
Use equation (1) in above equation :
[tex]v_{rms}=\sqrt{3\times \dfrac{RT}{M}}\\\\v_{rms}=\sqrt{3\times 101250} \\\\v_{rms}=551.13\ m/s[/tex]
It is clear that the RMS speed of the gas molecule is greater than 450 m/s.
