find the amount each contestant would carry if the total amount carried (5 cups) was redistributed equally among all the contestants.

Respuesta :

Complete Question

The line plot shows the amount of green ooze (in cup) carried by ten contestants. Find the amount each contestant would carry if the total amount carried (5 cups) was redistributed equally among all the contestants.

Answer:

1/2 Cup

Step-by-step explanation:

This is a Line Plot in which:

  • 1/4 had two Xs
  • 3/8 had two Xs
  • 1/2 had two Xs
  • 5/8 had three Xs
  • 7/8 had one Xs

Total

[tex]=(\frac{1}{4}X2) +(\frac{3}{8}X2) +(\frac{1}{2}X2) +(\frac{5}{8}X3) +(\frac{7}{8}X1) \\\\=\frac{2}{4} +\frac{6}{8} +1 +\frac{15}{8} +\frac{7}{8}\\\\$=5 Cups[/tex]

If this amount was redistributed equally among the ten contestants:

Each contestant would carry (5/10) cups =1/2 cup.

Ver imagen Newton9022