Answer: The required probability is 0.79
Step-by-step explanation:
Given: P(A) = 0.14
P(B) = 0.24
P(A and B) = 0.19
To find: P(A given B)
The conditional probability of an event A is the probability that the event will occur given the knowledge of an already occurred event B and is denoted by
[tex]P(A/B)[/tex] or [tex]P(A \text { given } B)[/tex] where the value of [tex]P(A/B)= \dfrac{P(A \text { and } B)}{P(B)}[/tex]
So we have
[tex]P(A/B) = \dfrac{0.19}{0.24} \approx 0.79[/tex]
Hence ,the required probability is 0.79
