Answer:
Correct option: (C) 83%.
Step-by-step explanation:
It is provided that the toxicity level of a lake is found by dividing the amount of dissolved toxins the lake water currently has per liter by the maximum safe amount of dissolved toxins that the water can hold per liter and then converting it to a percentage.
Denote the variables as follows:
x = amount of dissolved toxins the lake water currently has per liter
y = maximum safe amount of dissolved toxins that the water can hold per liter
The amount of dissolved toxins per liter of water in the river is, x = 0.86 mg/lt.
The maximum safe amount of dissolved toxins that the river water can hold is, y = 1.04 mg/lt.
Compute the toxicity level of the river water as follows:
[tex]\text{Toxicity level}=\frac{x}{y}\times 100[/tex]
[tex]=\frac{0.86}{1.04}\times 100\\\\=82.69231\%\\\\\approx 83\%[/tex]
Thus, the toxicity level of the river water is 83%.
The correct option is (C).