A gas sample occupies 8.77 L at 20 degrees Celsius and 3.98 atm. What is
the amount of mols of gas in the sample? *

Respuesta :

Answer:

1.45 mol

Explanation:

Given data

  • Volume of the gas (V): 8.77 L
  • Temperature of the gas (T): 20 °C
  • Pressure of the gas (P): 3.98 atm

Step 1: Calculate the absolute temperature (Kelvin)

We will use the following expression.

[tex]K = \°C + 273.15\\K = 20\°C + 273.15 = 293K[/tex]

Step 2: Calculate the number of moles (n) of the gaseous sample

We will use the ideal gas equation.

[tex]P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{3.98atm \times 8.77L}{\frac{0.0821atm.L}{mol.K} \times 293K} = 1.45 mol[/tex]