angeljohnson2914 angeljohnson2914

07-05-2020
Chemistry

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a sample of oxygen occupies 75 L at 1 atm. If the volume double what is the new pressure of oxygen in atm

Respuesta :

Manetho Manetho

08-05-2020

Answer:

[tex]P_2=\frac{1}{2} \text{ atm}[/tex]

Explanation:

Considering ideal gas situation and initial condition as 1 and final condition as 2 all other conditions being constant we get

[tex]P_1V_1=P_2V_2[/tex]

Here P1 = 1 atm , V1= 75L, also, V2=2V1 = 2×75 L =150 L

using above equation we have

[tex]1\times75=150\times P_2\\P_2=\frac{75}{150} = \frac{1}{2} \text{ atm}[/tex]

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