Answer:
Explanation:
mass ratio of oxygen and nitrogen in air at Miami
= 21 : 79
ratio of their moles
= [tex]\frac{21}{32} : \frac{79}{28}[/tex] ( mol weight of oxygen is 32 and of nitrogen is 28 )
= .65625 : 2.8214
= 1 : 4.3
This ratio will also be maintained in the air of Denver though total pressure decreases there.
Partial pressure of oxygen in air at both the places
mole fraction of oxygen
= [tex]\frac{1}{( 1 +4.3)}[/tex]
= .18868
partial pressure of oxygen at Denver
= .18868 x .83 x 760
= 119 mm.
