Answer:
Heat capacity of hydrocarbon is 1.73 J/(g.[tex]^{0}\textrm{C}[/tex] )
Explanation:
Heat capacity of the hydrocarbon = [tex]\frac{q}{m.\Delta T}[/tex] , where q is the amount of heat added, m is mass of hydrocarbon and [tex]\Delta T[/tex] is the rise in temperature.
Here q = 9.54 kJ = [tex]9.54\times 10^{3}[/tex] J, m = 225.0 g and [tex]\Delta T[/tex] = (45.0-20.5) [tex]^{0}\textrm{C}[/tex] = 24.5 [tex]^{0}\textrm{C}[/tex]
So, heat capacity of hydrocarbon = [tex]\frac{9.54\times 10^{3}J}{(225.0g)\times (24.5^{0}\textrm{C})}[/tex] = 1.73 J/(g.[tex]^{0}\textrm{C}[/tex] )
