Answer:[tex]f_e=16.22\ cm[/tex]
Explanation:
Given
Focal length of objective lens is [tex]f_o=89.7\ cm[/tex]
angular magnification is [tex]m_a=-5.53[/tex]
Angular magnification depends on the focal length of objective and eye piece
i.e.
[tex]m_a=-\frac{f_o}{f_e}[/tex]
[tex]f_e=-\frac{f_o}{m_a}[/tex]
[tex]f_e=-\frac{89.7}{-5.53}[/tex]
[tex]f_e=16.22\ cm[/tex]