Respuesta :

5328233

Answer:

a. a 1,000-kg car

Explanation:

Q: F = ma

(a) F = 100n

    M = 1000vg

    A = ?

--> F = ma  

--> a = f/m

     a = 1000/1000                                                                                                                                        a= 1m/8*2                                                                                                                                           (b)   F = 1000N

      m = 2000 vg

       a = ?

--> F = ma

     a = f/m

     a = 1000/2000

     a = 0.5 m/8*2

nuhulawal20

a) The acceleration of the engine of the [tex]1000kg[/tex] mass of car is 1m/s².

b) The acceleration of the engine of the [tex]2000kg[/tex] mass of car is 0.5m/s².

Given the data in the question;

  • Mass of car 1; [tex]m_1 = 1000kg[/tex]
  • Mass of car 2; [tex]m_2 = 2000kg[/tex]
  • Force exerted; [tex]F = 1000N[/tex]

To determine the acceleration of each of the two cars,  we use Newton's Second Law of Motion:

[tex]F = m*a[/tex]

Where m is mass of the object and a is the acceleration.

For Car 1 { mass 1000kg}

[tex]1000N = 1000kg * a\\\\1000kgm/s^2 = 1000kg * a\\\\a = \frac{1000kgm/s^2}{1000kg}\\\\a = 1m/s^2[/tex]

Therefore, given the force exerted, the acceleration of the engine of a [tex]1000kg[/tex] mass of car is 1m/s².

For Car 2 { mass 2000 kg }

[tex]1000N = 2000kg * a\\\\1000kgm/s^2 = 2000kg * a\\\\a = \frac{1000kgm/s^2}{2000kg}\\\\a = 0.5m/s^2[/tex]

Therefore, given the force exerted, the acceleration of the engine of a [tex]2000kg[/tex] mass of car is 0.5m/s².

Learn  more: https://brainly.com/question/18503017

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