Suppose a normal distribution has a mean of 26 and a standard deviation of

4. What is the probability that a data value is between 28 and 35? Round your

answer to the nearest tenth of a percent.

O A. 27.6%

O B. 29.6%

O c. 23.6%

OD. 25.6%

Respuesta :

What is [tex]z[/tex] score?

The [tex]$z$[/tex] score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

[tex]$z=\frac{\left( \text{Raw score }-\text{ Mean} \right)}{\text{Standard deviation}}$[/tex]

How to determine the [tex]z[/tex] score?

Given that:

Mean of 26 and a standard deviation of 4, For:

[tex]x=28[/tex]

[tex]=\frac{(28-26)}{4}\\ =\frac{2}{4}\\ =\frac{1}{2}\\ =0.5[/tex]

For [tex]x=35[/tex]

[tex]=\frac{(35-26)}{4}\\ =\frac{9}{4}\\ =2.25[/tex]

Now, compare the values.

[tex]$P(0.5 < z < 2.25)$[/tex]

[tex]$P(z < 2.25)-P(z < 0.5)$[/tex]

Learn more about [tex]z[/tex] score at- https://brainly.com/question/16206519

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Answer: 29.6%

Step-by-step explanation:

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