What is the molar it y of a solution of NaCl if 500.0 ml of solution contains 11.6 g of NaCl?

Answer:
0.397 M
Explanation:
Molarity = number of mole solute/number of L solution
M(NaCl) = 23.0 +35.5 = 58.5 g/mol
11.6 g* 1 mol/58.5 g = 0.1983 mol NaCl
500.0 mL = 0.5000 L
0.1983 mol NaCl/0.5000 L solution = 0.397 mol/L = 0.397 M