Answer:
14 units
Step-by-step explanation:
Both points lie on the vertical line x=32, so the distance between them is the difference of their y-coordinates:
29 -15 = 14 . . . . units
The two points are 14 units apart.
Answer:
[tex] d = \sqrt{(32-32)^2 +(15-29)^2} = \sqrt{196}= 14[/tex]
So then we can conclude that the smallest distance between the point A (32,15) and the point B(32,39) is 14
Step-by-step explanation:
When we have a two points on a dimensional space A and B we can find the distance between the two points with the following formula:
[tex] d= \sqrt{(x_A -x_B)^2 +(y_A -y_B)^2}[/tex]
Where (x_A,y_A) represent the coordinates for the point A and (x_B,y_B) represent the coordinates for the point B. And we know that the coordinates are :
A= (32,15) and B= (32,29)
And replacing in the formula for the distance we got:
[tex] d = \sqrt{(32-32)^2 +(15-29)^2} = \sqrt{196}= 14[/tex]
So then we can conclude that the smallest distance between the point A (32,15) and the point B(32,39) is 14
