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Once you’ve identified the initial and final conditions, you’re ready to solve for the unknown quantity in your problem. Boyle’s Law expresses the pressure-volume relationship as P1V1=P2V2, so you will need to solve this equation for the unknown quantity and then plug in your known values to calculate the unknown. What pressure would it take to compress 250. L of helium gas initially at 1.00 atm into a 2.00 L tank at constant temperature? Express your answer with the appropriate units.

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Rau7star

Answer:

125atm

Explanation:

Given:

initial pressure [tex]P_{1[/tex]= 1 atm

initial volume  [tex]V_{1[/tex]= 250L

final volume  [tex]V_{2[/tex]=2L

Required:

Final Pressure  [tex]P_{2[/tex]=?

As Boyle’s Law expresses the pressure-volume relationship as

[tex]P_{1[/tex][tex]V_{1[/tex]= [tex]P_{2[/tex] [tex]V_{2[/tex]

(1)(250)= [tex]P_{2[/tex] (2)

[tex]P_{2[/tex] = 250/2

[tex]P_{2[/tex]=125atm

Therefore, it would take pressure of 125atm.

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