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On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4). The dashed-line parabola, labeled g of x, goes through (negative 6, 10), has a vertex at (negative 4, 6), and goes through (negative 2, 10).

What is the equation of the translated function, g(x), if

f(x) = x2?


g(x) = (x – 4)2 + 6

g(x) = (x + 6)2 – 4

g(x) = (x – 6)2 – 4

g(x) = (x + 4)2 + 6

Respuesta :

xero099

Answer:

[tex]y = (x+4)^{2}+6[/tex]

Step-by-step explanation:

The parabola with vertex at point (h,k) is described by the following model:

[tex]y - k = C\cdot (x-h)^{2}[/tex]

The equation which satisfies the conditions described above:

[tex]y - 6 = (x+4)^{2}[/tex]

[tex]y = (x+4)^{2}+6[/tex]

The two points are evaluated herein:

x = -6

[tex]y =(-6+4)^{2}+6[/tex]

[tex]y = (-2)^{2}+6[/tex]

[tex]y = 4 + 6[/tex]

[tex]y = 10[/tex]

x = -2

[tex]y = (-2+4)^{2}+6[/tex]

[tex]y = 2^{2} + 6[/tex]

[tex]y = 4 + 6[/tex]

[tex]y = 10[/tex]

The equation of the translated function is [tex]y = (x+4)^{2}+6[/tex].

The answer is D  just took the test.

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