Answer:
The distance to the Eath's Horizon from point P is 352.8 mi, approximately.
Step-by-step explanation:
You observe the problem from a graphical perspective with the image attached.
Notice that side [tex]x[/tex] is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.
We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.
The hypothenuse is 3959 + 15.6 = 3974.6 mi.
[tex](3974.6)^{2}=x^{2} +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8[/tex]
Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.
