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What are the x- and y-coordinates of point E, which partitions

the directed line segment from A to B into a ratio of 1:2?

x = ( min )(x2 – x1) + x1

v = l m on Jiva – vi] + vi

(0, 1)

0 (-1,3)

* (-2,5)

(1,0)

Respuesta :

Complete question:

What are the x- and y- coordinates of point E, which partitions the directed line segment from [tex]A\:(- 4,\:9) \:to\: B\:(2,\:- 3)[/tex] into a ratio of 1 : 2.

Answer:

(C) (-2,5)

Step-by-step explanation:

[tex]x = (\dfrac{m}{m+n}) (x_2-x_1) + x_1\\\\y = (\dfrac{m}{m+n}) (y_2-y_1) + y_1[/tex]

[tex](x_1,y_1)=(- 4,\:9),(x_2,y_2)=B\:(2,\:- 3)[/tex]

m=1, n=2

[tex]x = \left(\dfrac{1}{1+2}\right) (2-(-4)) + (-4)\\=\left(\dfrac{1}{3}\right) (2+4)-4\\=\left(\dfrac{6}{3}\right)-4=2-4\\x=-2[/tex]

[tex]y = \left(\dfrac{1}{1+2}\right) (-3-9) + 9\\=\left(\dfrac{1}{3}\right) (-12)+9\\=\left(-\dfrac{12}{3}\right)+9=-4+9\\y=5[/tex]

The x- and y-coordinates of the point E is (-2,5)