Answer:
Step-by-step explanation:
When m=6
(1) The difference of the product of 3 and m minus the quotient of m divided by 2
[tex]3m-\dfrac{m}{2}\\=3(6)- \dfrac{6}{2}\\=18-3\\=15[/tex]
(2)The sum of 3 times m and 4 times m
3m+4m
=3(6)+4(6)
=18+24
=42
(3)The quotient of 6 divided by the difference of m minus 3
[tex]\dfrac{6}{m-3} =\dfrac{6}{6-3} =\dfrac{6}{3} =2[/tex]
(4)The sum of m and 3 divided by the difference of m minus 3
[tex]\dfrac{m+3}{m-3}= \dfrac{6+3}{6-3}=\dfrac{9}{3}=3[/tex]