Answer:
Option C.
Step-by-step explanation:
Number of purple markers = 2
Number of black marker = 1
Number of red markers = 3
Number of yellow markers = 2
Number of blue markers = 2
Total number of markers = 10
Probability to select randomly a red marker = [tex]\frac{\text{Number of red markers}}{\text{Total number of markers}}[/tex]
= [tex]P(red)=\frac{3}{10}[/tex]
Now we keep with us and randomly select a marker again.
So remaining markers with us = (10 - 1) = 9
Probability of the randomly selected marker to be yellow P(yellow)
= [tex]\frac{\text{Number of yellow markers}}{\text{Number of remaining markers}}[/tex]
= [tex]\frac{2}{9}[/tex]
Probability of both the events (selecting red AND yellow) = P(red) × P(yellow)
= [tex]\frac{3}{10}\times \frac{2}{9}[/tex]
= [tex]\frac{6}{90}[/tex]
= [tex]\frac{1}{15}[/tex]
Therefore,Option (C) will be the answer.