Answer:
The limiting reactant is Carbon dioxide, [tex]CO_{2}[/tex]
Explanation:
The balanced reaction equation is:
[tex]2NH_{3} + CO_{2}[/tex] → [tex]CH_{4} N_{2} O + H_{2} O[/tex]
The mole ratio of ammonia to carbon dioxide is 2:1
142100/17g = 8358.8 mol of NH3
211400/44g = 4, 804.5 mole of CO2
Now:
4,804.5 mol of CO2 × [tex]\frac{2 mol NH_{3} }{1 molCO_{2} }[/tex] = 9,609 mol of NH3 present
8,358.8 mole of NH3 × [tex]\frac{1 moleCO_{2} }{2moles NH_{3} }[/tex] = 4,179.4 mol of CO2 present
NH3 needs 8, 358.8 moles but had 9, 609 moles⇒ excess reactant
CO2 needs 4, 804,5 mol but had 4, 179.4 moles⇒ limiting reactant (used up completely)
The limiting reactant is carbon dioxide, CO2.